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8x^2-63x+90=0
a = 8; b = -63; c = +90;
Δ = b2-4ac
Δ = -632-4·8·90
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-33}{2*8}=\frac{30}{16} =1+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+33}{2*8}=\frac{96}{16} =6 $
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